(y-5)(2y^2-4y-1)=

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Solution for (y-5)(2y^2-4y-1)= equation:


Simplifying
(y + -5)(2y2 + -4y + -1) = 0

Reorder the terms:
(-5 + y)(2y2 + -4y + -1) = 0

Reorder the terms:
(-5 + y)(-1 + -4y + 2y2) = 0

Multiply (-5 + y) * (-1 + -4y + 2y2)
(-5(-1 + -4y + 2y2) + y(-1 + -4y + 2y2)) = 0
((-1 * -5 + -4y * -5 + 2y2 * -5) + y(-1 + -4y + 2y2)) = 0
((5 + 20y + -10y2) + y(-1 + -4y + 2y2)) = 0
(5 + 20y + -10y2 + (-1 * y + -4y * y + 2y2 * y)) = 0
(5 + 20y + -10y2 + (-1y + -4y2 + 2y3)) = 0

Reorder the terms:
(5 + 20y + -1y + -10y2 + -4y2 + 2y3) = 0

Combine like terms: 20y + -1y = 19y
(5 + 19y + -10y2 + -4y2 + 2y3) = 0

Combine like terms: -10y2 + -4y2 = -14y2
(5 + 19y + -14y2 + 2y3) = 0

Solving
5 + 19y + -14y2 + 2y3 = 0

Solving for variable 'y'.

The solution to this equation could not be determined.

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